HCl with Cu ,net ionic equation
The net ionic equation for the reaction between hydrochloric acid (HCl) and copper (Cu) can be determined by first writing the balanced chemical equation and then canceling out the spectator ions.
1. Write the balanced chemical equation for the reaction:
HCl + Cu → CuCl2 + H2
2. Separate the aqueous compounds into their respective ions:
H+ + Cl- + Cu → Cu2+ + 2Cl- + H2
3. Cancel out the spectator ions (ions that appear on both sides of the equation):
H+ + Cu → Cu2+ + H2
This is the net ionic equation for the reaction between HCl and Cu. It shows the essential ions involved in the reaction.
To determine the net ionic equation for the reaction between hydrochloric acid (HCl) and copper (Cu), we first need to write out the balanced chemical equation for the reaction.
The chemical equation for the reaction between hydrochloric acid and copper can be written as:
2 HCl(aq) + Cu(s) → CuCl2(aq) + H2(g)
This balanced equation indicates that two moles of hydrochloric acid react with one mole of copper to produce one mole of copper(II) chloride and one mole of hydrogen gas.
To write the net ionic equation, we need to remove any spectator ions – ions that appear on both sides of the equation and do not participate in the reaction. In this case, the hydrochloric acid dissociates completely into H+ and Cl- ions in aqueous solution, but copper does not undergo any change in charge. Therefore, the Cu2+ ion is a spectator ion in this reaction.
The net ionic equation for the reaction between HCl and Cu can be written as:
2 H+(aq) + 2 Cl-(aq) → H2(g)
This net ionic equation shows that two hydrogen ions from the hydrochloric acid react with two chloride ions to produce hydrogen gas.
Note that the net ionic equation does not include the spectator ion, Cu2+.