"If you have an inductor that is connected to a 36v, 400 Hz circuit with a current of .2 A, what is the inductance of the inductor?"
V=I*Z
V=I*2PI*f*L solve for L
36/(2*PI*400)=
To find the inductance of the inductor, we can use the formula:
L = (V / (I * 2 * π * f))
Where:
L is the inductance in henries (H)
V is the voltage in volts (V)
I is the current in amperes (A)
π is a mathematical constant approximately equal to 3.14159
f is the frequency in hertz (Hz)
In this case:
V = 36V (voltage)
I = 0.2A (current)
f = 400Hz (frequency)
Substituting these values into the formula, we have:
L = (36V / (0.2A * 2 * π * 400Hz))
Calculating this expression:
L ≈ 36V / (0.2A * 2 * 3.14159 * 400Hz)
L ≈ 36V / (0.2A * 2513.27412)
L ≈ 36V / 502.654824A
L ≈ 0.0716H
Therefore, the inductance of the inductor is approximately 0.0716 henries (H).