If [x-y]^2=12 , and xy=2 .
Find x^2+y^2. pl help.
[x-y]^2= x^2+y^2-2xy
12= x^2+Y^2-2*2
So, x^2+Y^2=12+4=16 Is this correct sir ?.
looks good to me
thank you sir.
To find x^2 + y^2 given the equations [x-y]^2 = 12 and xy = 2, we can start by expanding [x-y]^2.
[x-y]^2 = (x-y)(x-y) = x^2 -2xy + y^2
Since we know that [x-y]^2 = 12, we can substitute this into the expanded equation:
12 = x^2 -2xy + y^2
Next, substitute xy = 2 into the equation:
12 = x^2 - 2(2) + y^2
12 = x^2 - 4 + y^2
Now, we need to isolate x^2 + y^2, so we can rearrange the equation:
x^2 + y^2 = 12 + 4
x^2 + y^2 = 16
Therefore, x^2 + y^2 is equal to 16.
In summary, the value of x^2 + y^2 is 16.