inverse trig function
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Please can you help me with this question? Choose the option which is a false statement: A arctan(tan2/3pi))=1/3pi B arccos(cos(3/4pi))=3/4pi C sin(arcsin(1/2pi))=1/2pi D arcsin(1/2squareroot3)=1/3pi E arcsin(sin(3/4pi))=1/4pi
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Evaluate please: a.) arcsin(sin 13pi/16) b.) arccos(cos[pi/18]) c.) arcsin(sin pi/18 d.) arcsec(√2) e.) arctan(√3/3)
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Book works out integral of sqtr(a^2x^2)dx as a^2/2*arcsin(x/a)+x/2*sqrt(a^2x^2) by taking x=a sin theta, and advises to work it out using x=a cos theta. I did and got the first term as a^2/2*arccos(x/a)and the same second term.
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Write the trigonometric expression as an algebraic expression. 1.) SIN(ARCSIN X+ARCCOS X) ANSWER: 1 2.) SIN(ARCTAN 2XARCCOS X) ANSWER: 2x²SquareRoot of 1x²/Square Root of 4x²+1.
asked by AwesomeGuy on February 21, 2013 
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Eliminate the parameter (What does that mean?) and write a rectangular equation for (could it be [t^2 + 3][2t]?) x= t^2 + 3 y = 2t Without a calculator (how can I do that?), determine the exact value of each expression. cos(Sin^1
asked by Anonymous on August 3, 2007 
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Evaluate. 1. sin^1(1/2) 2. cos^1[(root 3)/2] 3. arctan[(root3)/3] 4. cos(arccos2/3) 5. arcsin(sin 2pi) 6. sin(arccos 1)
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solve for x in the following equations: 1) sin(arcsin x) = 1 2) 2arcsin x = 1 3) cos(arccos x) = 1/3
asked by Abbey on January 8, 2012 
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Evaluate. 1. sin^1(1/2) 2. cos^1[(root 3)/2] 3. arctan[(root3)/3] 4. cos(arccos2/3) 5. arcsin(sin 2pi) 6. sin(arccos 1) I got these values as my answers: 1. pi/6 2. 5pi/6 3. pi/6 4. 2/3 5. 2pi 6. 0 Can someone please tell me
asked by anonymous on January 7, 2010 
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Suppose f(x) = sin(pi cos(x)). On any interval where the inverse function y = f^1(x) exists, the derivative of f^1(x) with respect to x is: I've come as far as y = arccos ((arcsin(x))/pi), but I am not certain this is right.
asked by Mooch on March 15, 2012