Nigel has 2 dogs.one dog eats 4and one half pounds of food each week, and the other dog eats 1/8 pounds. how much do the dogs eat in one week?
Is that right? One dog only eats 1/8 of a pound of food a week???
Ms. sue it not right it wrong wrong
4 1/2 + 1/8 = 9/2 + 1/8 = 36/8 + 1/8 = 37/8 = 4 5/8 Lbs/wk.
The dog that eats only 1/8 Lbs/wk is on a diet!1 LOL.
To find out how much food the dogs eat in one week, we need to add the amounts of food each dog consumes.
First, let's calculate how much the first dog eats: one dog eats 4 and one half pounds of food each week. We can write this as 4 1/2 pounds, which is the same as 9/2 pounds.
Next, let's calculate how much the second dog eats: one dog eats 1/8 pounds of food each week.
To add these amounts together, we'll convert the second dog's food amount to fractions with a common denominator:
9/2 + 1/8
To add these fractions, we need to have a common denominator. The least common multiple of 2 and 8 is 8. Let's convert both fractions to have a denominator of 8:
(9/2) * (4/4) + (1/8) * (1/1)
This simplifies to:
36/8 + 1/8
Now we can add these fractions:
(36 + 1) / 8
This gives us:
37 / 8
So, the dogs eat a total of 37/8 pounds of food in one week.