-[3(2x-1)+x]=2[x-2(5x+4)]
this isn't really homework but my teacher said you can pick a partner to study with. So we're giving each other hard questions and I don't understand this, nor do I know where my partner got this question from. any help would be appreciated.
(I have some work written down for this already but its kind of messy and unorganized so if I tried to type it here then.... idk)
-[3(2x-1)+x]=2[x-2(5x+4)]
-[6x-3+x]=2[x-10x - 8]
-[7x-3]=2[-9x - 8]
- 7x + 3 = -18x - 16
11x = -19
x = -19/11
Oh. Thanks guys, that really helped.
No problem, I can help you solve this equation step by step. Let's start by simplifying both sides of the equation:
-[3(2x-1)+x]=2[x-2(5x+4)]
First, distribute the 3 on the left side of the equation:
-[6x - 3 + x] = 2[x - 2(5x + 4)]
Simplify inside the parentheses:
-6x + 3 - x = 2[x - 10x - 8]
Combine like terms on both sides:
-7x + 3 = 2[x - 10x - 8]
Next, distribute the 2 on the right side:
-7x + 3 = 2x - 20x - 16
Combine like terms on the right side:
-7x + 3 = -18x - 16
Now, let's isolate the variable x. To do that, we need to get all the x terms on one side and constants on the other side.
Add 18x to both sides of the equation:
11x + 3 = -16
Then, subtract 3 from both sides of the equation:
11x = -19
Finally, divide both sides by 11:
x = -19/11
So, the solution to the given equation is x = -19/11.
I hope this helps! Let me know if you have any further questions or need more explanations.