742.5 J of energy is used to heat an unknown mass of aluminum from 10° C to 65.0° C. The specific heat capacity of aluminum = 0.90 J/(g·°C).
What is the mass of the aluminum?
Thats not correct
742.5/(.9*55) = 15
so it would be 15 grams
To find the mass of the aluminum, we can use the formula:
Q = mcΔT
Where:
Q = heat energy transferred (in Joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/(g·°C))
ΔT = change in temperature (in °C)
We are given:
Q = 742.5 J
c = 0.90 J/(g·°C)
ΔT = (65.0°C - 10.0°C) = 55.0°C
Substituting the values into the formula, we have:
742.5 J = m * 0.90 J/(g·°C) * 55.0°C
Now solve for mass (m):
m = 742.5 J / (0.90 J/(g·°C) * 55.0°C)
m = 742.5 J / (49.5 J/(g·°C))
m ≈ 14.95 g
Therefore, the mass of the aluminum is approximately 14.95 grams.