If the latent heat of fusion for water is 333.4 J/g, how much heat is required to melt 170 grams of ice at 0 °C?
what is 170*333.4 Joules?
Did you ever figure out the answer?
To calculate the heat required to melt the ice, you can use the formula:
Q = m * L_f
Where:
Q is the heat required (in joules),
m is the mass of the ice (in grams),
L_f is the latent heat of fusion for water (in joules per gram).
Given:
m = 170 grams
L_f = 333.4 J/g
Substituting these values into the formula, we get:
Q = 170 grams * 333.4 J/g
Q = 56,678 joules
Therefore, 56,678 joules of heat is required to melt 170 grams of ice at 0 °C.
To find out how much heat is required to melt 170 grams of ice at 0 °C, we can use the formula:
Q = m * L
Where:
Q is the heat energy
m is the mass of the substance
L is the latent heat of fusion
In this case, the mass of ice is 170 grams, and the latent heat of fusion for water is given as 333.4 J/g.
Substituting the given values into the formula, we have:
Q = 170g * 333.4 J/g
Now we can calculate the answer:
Q = 56978 J
Therefore, it would require 56,978 J of heat to melt 170 grams of ice at 0 °C.