For 1 and 2, use integer values of x from -3 to 3 to graph the equation

(1) y = -2x2 + 3
(2x squared)

(2) y = 1/3 |x| -2
(x is in absolute value)

you can compare your graphs with these

http://www.wolframalpha.com/input/?i=plot+y+%3D+-2x%5E2+%2B+3,+y+%3D+1%2F3+%7Cx%7C+-2

desmos.com is also a great web site

To graph the equations, you need to substitute different integer values of x within the given range and calculate the corresponding values of y. Once you have a set of points, you can plot them on a graph.

(1) For the equation y = -2x^2 + 3, let's substitute integer values of x from -3 to 3:

For x = -3, y = -2(-3)^2 + 3 = -2(9) + 3 = -18 + 3 = -15.
So, we have the point (-3, -15).

For x = -2, y = -2(-2)^2 + 3 = -2(4) + 3 = -8 + 3 = -5.
So, we have the point (-2, -5).

For x = -1, y = -2(-1)^2 + 3 = -2(1) + 3 = -2 + 3 = 1.
So, we have the point (-1, 1).

For x = 0, y = -2(0)^2 + 3 = -2(0) + 3 = 0 + 3 = 3.
So, we have the point (0, 3).

For x = 1, y = -2(1)^2 + 3 = -2(1) + 3 = -2 + 3 = 1.
So, we have the point (1, 1).

For x = 2, y = -2(2)^2 + 3 = -2(4) + 3 = -8 + 3 = -5.
So, we have the point (2, -5).

For x = 3, y = -2(3)^2 + 3 = -2(9) + 3 = -18 + 3 = -15.
So, we have the point (3, -15).

Plot these points on a graph, connect them with a smooth curve, and you will have the graph of the equation y = -2x^2 + 3.

(2) For the equation y = 1/3 |x| - 2, let's substitute integer values of x from -3 to 3:

For x = -3, y = 1/3 |-3| - 2 = 1/3 (3) - 2 = 1 - 2 = -1.
So, we have the point (-3, -1).

For x = -2, y = 1/3 |-2| - 2 = 1/3 (2) - 2 = 2/3 - 2 = -4/3.
So, we have the point (-2, -4/3).

For x = -1, y = 1/3 |-1| - 2 = 1/3 (1) - 2 = 1/3 - 2 = -5/3.
So, we have the point (-1, -5/3).

For x = 0, y = 1/3 |0| - 2 = 0 - 2 = -2.
So, we have the point (0, -2).

For x = 1, y = 1/3 |1| - 2 = 1/3 (1) - 2 = 1/3 - 2 = -5/3.
So, we have the point (1, -5/3).

For x = 2, y = 1/3 |2| - 2 = 1/3 (2) - 2 = 2/3 - 2 = -4/3.
So, we have the point (2, -4/3).

For x = 3, y = 1/3 |3| - 2 = 1/3 (3) - 2 = 1 - 2 = -1.
So, we have the point (3, -1).

Plot these points on a graph, connect them with a smooth curve, and you will have the graph of the equation y = 1/3 |x| - 2.