So I figured out how to do the first 6, how do I do the remaining?

7. Evaluate the function below over the domain {-1, 0,
1, 2}. As the values of the domain increase, do the
values of the function increase or decrease?

y = (3/4)ˣ

8. Suppose an investment of $5,000 doubles every 12
years. How much is the investment worth after 36
years? After 48 years?
Write and solve an exponential equation.

9. Does the function represent exponential growth or
exponential decay? Identify the growth or decay
factor.

= 9 ∙ (1/2)ˣ

10. You deposit $520 in an account with 4% interest
compounded monthly. What is the balance in the
account after 5 years?

To solve the remaining questions, I'll walk you through the steps for each one.

7. To evaluate the function y = (3/4)^x over the domain {-1, 0, 1, 2}, substitute each value from the domain into the function and calculate the corresponding output. For example:
- For x = -1: y = (3/4)^(-1) = 4/3
- For x = 0: y = (3/4)^0 = 1
- For x = 1: y = (3/4)^1 = 3/4
- For x = 2: y = (3/4)^2 = 9/16
After evaluating the function for each value in the domain, check if the values of the function increase or decrease as the values of the domain increase. In this case, you can see that as the values of the domain increase, the values of the function decrease.

8. The investment doubles every 12 years. This means that the investment grows exponentially with a doubling time of 12 years. To calculate the worth of the investment after 36 years, you can write the exponential equation: P = P₀ * (2^(t/d)), where P₀ is the initial investment, t is the number of years, d is the doubling time, and P is the final worth of the investment. Substitute the given values into the equation: P = $5,000 * (2^(36/12)) = $5,000 * 2³ = $5,000 * 8 = $40,000. Similarly, to find the worth after 48 years: P = P₀ * (2^(48/12)) = $5,000 * (2^4) = $5,000 * 16 = $80,000.

9. The function y = 9 * (1/2)^x represents exponential decay. An exponential decay function has a base between 0 and 1. In this case, the base is 1/2, which is between 0 and 1. The growth or decay factor for this function is 1/2, which means the function decreases by half with each increase in x.

10. To find the balance in the account after 5 years, you can use the formula for compound interest: A = P(1 + r/n)^(nt), where A is the final balance, P is the principal amount, r is the annual interest rate (expressed as a decimal), n is the number of times the interest is compounded per year, and t is the number of years. Substitute the given values into the formula: A = $520(1 + 0.04/12)^(12*5) ≈ $520(1.0033)^(60) ≈ $520(1.2061) ≈ $627.13. The balance in the account after 5 years is approximately $627.13.