Jacob weighs 64 pounds together he and his sister wait 8 pounds more than two times a week and sisters what is the weight ,w,of Jacobs sister
Ans: 64+w = 2w + 8; 56 pounds
Jacob(J) = 64lbs
J+w=8+(2w)
64+w=8+2w
64-8=2w-w
56=w
*I got the answer nvm* :/
A. 64+w=2w+8;56 pounds
B.64+w-8=2w;62 pounds
C. 64+w=2w;64 pounds
D. 64+w=2w-8; 72 pounds
which one?
Please help me with this one
Again with proofreading.
"wait 8 pounds more than two times a week"?
Jacob weights 64 pounds . Together , he his sister weigh eight pounds more than two times the weight of his sister . What is the weight ,w, of Jacobs sister?
To find the weight of Jacob's sister, let's break down the given information:
1. Jacob weighs 64 pounds.
2. Together, Jacob and his sister weigh 8 pounds more than two times his sister's weight.
Let's assume Jacob's sister's weight is represented by "w."
According to the information given, the combined weight of Jacob and his sister is equal to 8 pounds more than two times the weight of his sister. Mathematically, this can be represented as:
Jacob's weight + sister's weight = 2 * sister's weight + 8
Since Jacob's weight is 64 pounds, we can substitute this value into the equation:
64 + sister's weight = 2 * sister's weight + 8
Now, we can solve this equation to find the weight of Jacob's sister:
64 + sister's weight - 2 * sister's weight = 8
64 - sister's weight = 8
Subtract 64 from both sides:
- sister's weight = 8 - 64
- sister's weight = -56
To solve for the weight of Jacob's sister, we need to invert the sign of the weight. So, we have:
sister's weight = -(-56)
Therefore, the weight of Jacob's sister is 56 pounds.