How many real number solutions are there to the equation 0= -3x^2 + x -4 ?
a. 0 ***
b. 1
c. 2
d. 3
True! Because both the discriminant and the graph produce that solution : )
It is a quadratic with a vertex below the x-axis and it opens downward. b^2 - 4ac <0
To determine the number of real number solutions to the equation 0 = -3x^2 + x - 4, we need to consider the discriminant of the quadratic equation.
The discriminant (D) is calculated using the formula D = b^2 - 4ac, where the quadratic equation is in the form ax^2 + bx + c = 0.
In this case, the coefficients of the quadratic equation are a = -3, b = 1, and c = -4. Plugging these values into the discriminant formula, we have:
D = (1)^2 - 4(-3)(-4)
D = 1 - 48
D = -47
Since the discriminant (-47) is negative, we can conclude that there are no real number solutions to the equation.
Therefore, the correct answer is a. 0.