Although that should work fine Anonymous, you do not have to split the 100 cm ruler into sections left and right of the balance point. The weight of a rigid body acts as if it were all at the center of mass, no matter what forces are acting on it where.
A UNIFORM METER RULE IS PIVOTED AT P IN 80cm mark on the meter rule force 0.2 And 0.8N Are Applied At M The 60Cm Mark And Q The 90Cm Mark.If The Rule Is In Equilibrium .Find The Mass Of The Rule.Take g=10ms-2
The meterstick shown to the right is 100 cm long. It is free to pivot around its center of gravity (CG), which is at the 50-cm mark. There is a 25.0-N block hanging from the 80-cm mark. Decide where each of the other blocks should
A metre rule is found to balance at 51cm mark.When a body of 70g is suspended at the 10cm mark,the balance point is found to be at 25cm mark.Find the mass of the ruler and the distance of the balance point from the zero end,if the