Find the tension in the rope of an Atwood machine that has a 40 kg mass hanging on one side and
a 60 kg mass on the other.
see your other post, just change the angle to 90 deg
471N?? Idk if this is corrrect @bob
To find the tension in the rope of an Atwood machine, we need to consider the difference in masses on either side of the pulley and the acceleration of the system.
First, determine the net force acting on the system. In an Atwood machine, the net force is equal to the difference in masses (m2 - m1) multiplied by the acceleration (a), where m1 and m2 are the masses and a is the acceleration of the system.
In this case, the mass on one side is 40 kg and the mass on the other side is 60 kg. Therefore, the difference in masses is 60 kg - 40 kg = 20 kg.
Next, we need to determine the acceleration of the system. Since we haven't been given any additional information, we can assume that the system is operating under the influence of gravity. In this case, the acceleration will be the acceleration due to gravity, which is approximately 9.8 m/s^2.
Now, we can calculate the net force acting on the system using the formula:
Net Force = (m2 - m1) * a
Net Force = 20 kg * 9.8 m/s^2
Net Force = 196 N
Since the tension in the rope is equal to the net force acting on the system, the tension in the rope is 196 N.