A bag contains equal numbers of red, blue, and yellow marbles. A student chooses a marble at random. What is the relationship between the probability that the marble is red and the probability that the marble is not red?
A) P(red) = P(not red)
B) P(red) = - P(not red)
C) P(red) = P(not red) -1
D) P(red) = 1 - P(not red)
Is it B??
p red =1/3
p not red = 2/3
so
p red = 1 - p not red
IN OTHER WORDS
It is either red or not red, period
so Pred + Pnot red = 1
D
16
There are five teams in a basketball competition each team must play each of the other teams once how many games will each team play
the answer must be a because 4x4+16
In a burger there are an equal numbers of red blue and yellow marbles how many marbles could be in the bag
No, the correct answer is D) P(red) = 1 - P(not red).
To explain how to arrive at this answer, let's break it down step by step:
1. We know that the bag contains an equal number of red, blue, and yellow marbles. Let's assume there are n marbles of each color.
2. Therefore, the total number of marbles in the bag is 3n.
3. The probability of choosing a red marble can be calculated by dividing the number of red marbles (n) by the total number of marbles (3n), giving us P(red) = n/3n = 1/3.
4. The probability of choosing a marble that is not red can be calculated by subtracting the probability of choosing a red marble from 1. This gives us P(not red) = 1 - P(red) = 1 - 1/3 = 2/3.
Therefore, the relationship between the probability that the marble is red and the probability that the marble is not red is P(red) = 1 - P(not red), which corresponds to option D.
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