Write as a chemical reaction
Sodium phosphate + calcium chloride yield calcium + sodium chloride
My child has. Na3PO4 + CaCl -> Ca3Po4 + NaCl
Nope. Calcium Cloride is CaCl2 and calcium phosphate is Ca3(PO4)2
Kid should be able to balance it now.
The chemical equation you wrote is almost correct, but there is a small mistake in the formation of calcium phosphate. Let me correct it for you:
The balanced chemical equation for the reaction between sodium phosphate (Na3PO4) and calcium chloride (CaCl2) to form calcium phosphate (Ca3(PO4)2) and sodium chloride (NaCl) is as follows:
2 Na3PO4 + 3 CaCl2 → Ca3(PO4)2 + 6 NaCl
Here's how you can balance the equation:
Step 1: Write the chemical formulas of the reactants and products:
Sodium phosphate: Na3PO4
Calcium chloride: CaCl2
Calcium phosphate: Ca3(PO4)2
Sodium chloride: NaCl
Step 2: Count the number of atoms of each element on both sides of the equation:
Reactants:
- Sodium (Na): 3 on the left side, 6 on the right side (3 Na in Na3PO4 and 3 Na in 6 NaCl)
- Phosphorus (P): 1 on both sides
- Oxygen (O): 4 on the left side (3 in Na3PO4 and 1 in Ca3(PO4)2), 8 on the right side (4 in Ca3(PO4)2 and 4 in 6 NaCl)
- Calcium (Ca): 0 on the left side, 3 on the right side
- Chlorine (Cl): 6 on the left side (3 in CaCl2 and 3 in 6 NaCl), 6 on the right side
Step 3: Balance the atoms by adjusting the coefficients in front of the compounds:
To balance the sodium (Na) atoms, you need to have 2 Na3PO4 on the left side, resulting in 6 Na atoms on the right side.
To balance the chlorine (Cl) atoms, you need to have 3 CaCl2 on the left side, resulting in 6 Cl atoms on the left side and 6 Cl atoms on the right side.
To balance the phosphorus (P) and oxygen (O) atoms, you will need to have 1 Ca3(PO4)2 on the right side, which will give you 3 P and 8 O atoms on the right side.
The balanced equation is:
2 Na3PO4 + 3 CaCl2 → Ca3(PO4)2 + 6 NaCl