what is the exterior angle of a icosiepentagon? ( a 25-gon for short lol )? please i need help finding it

each exterior angle of an n-gon is 360/n degrees

You can see this by noting that traveling once around the perimeter involves n turns, adding up to 360 degrees.

so 360/25? = 9.000 or 14.4?

yes, 360/25

I leave it to you to decide which of the two values is correct...

To find the exterior angle of any polygon, including a 25-gon (or icosikaihenagon), you can use a simple formula:

Exterior Angle = 360° / Number of Sides

In this case, for a 25-gon, the formula becomes:

Exterior Angle = 360° / 25

To find the value, you can divide 360 by 25 using a calculator or long division:

360 ÷ 25 = 14.4°

Therefore, the exterior angle of a 25-gon (or icosikaihenagon) is 14.4 degrees.