24g of magnessium burn in air to form magnessium oxides as show below.
2Mg+o²=2Mgo
how much magnessium oxide is found in the product.
you get the same number of moles of MgO as you started with moles of Mg. So how many moles of Mg is 24 grams?
To determine the amount of magnesium oxide (MgO) formed, we need to calculate the stoichiometric ratio between magnesium (Mg) and magnesium oxide (MgO) using the balanced chemical equation provided. The ratio tells us how many moles of magnesium oxide are formed for every 2 moles of magnesium consumed.
From the equation:
2Mg + O2 → 2MgO
The ratio is:
2 moles of Mg : 2 moles of MgO
Since we have 24g of magnesium, we need to convert grams to moles using the molar mass of magnesium (24.31 g/mol). The calculation is as follows:
moles of Mg = mass / molar mass
moles of Mg = 24g / 24.31 g/mol
moles of Mg = 0.987 mol (approximately)
According to the stoichiometric ratio, for every 2 moles of Mg, we get 2 moles of MgO. Therefore, we can conclude that:
0.987 mol of Mg → 0.987 mol of MgO
Now, we need to convert moles of MgO back into grams. The molar mass of magnesium oxide (MgO) is 40.31 g/mol. Here's the calculation:
mass of MgO = moles of MgO × molar mass
mass of MgO = 0.987 mol × 40.31 g/mol
mass of MgO = 39.77 g (approximately)
Hence, approximately 39.77 grams of magnesium oxide (MgO) will be found in the product.