Triangle XYZ is reflected across the line x = 3. What is the reflection image of Y?
Triangle XYZ is reflected across the line x = 3. What is the reflection image of X?
such a reflection takes (x,y) -> (3-(x-3),y) = (6-x,y)
(4, 3)
To find the reflection image of a point, you need to find the point that is equidistant from the line of reflection as the original point.
In this case, the line of reflection is x = 3, which is a vertical line passing through x = 3.
To find the reflection image of Y, you need to find a point that has the same distance from the line x = 3 as Y.
Since Y is a point in the triangle XYZ, we can find its distance from the line x = 3 by subtracting the x-coordinate of Y from 3. Let's call this distance "d".
d = 3 - x-coordinate of Y
Once we have the distance "d", we can find the reflection image of Y by adding twice the distance "d" to the x-coordinate of Y. This is because the reflection image will be on the other side of the line of reflection, so the x-coordinate needs to move twice the distance away from the line.
Reflection image of Y = (3 + 2d, y-coordinate of Y)
So, to complete this calculation, you would need the coordinates of Y (x-coordinate, y-coordinate), which have not been provided in the question.