I have a problem i don't get...
H3PO4+3NaOH -> 3H2O+Na3PO4
How many moles of Na3PO4 will be produced from 1.7 moles of NaOH in the presence of excess H3PO4?
The equation tells you that 1 mol of Na3PO4 will be produced by 3 mol NaOH (that's one reason you balance the equation). So wouldn't that be 1/3 mol Na3PO4 for each mol NaOH. And you had 1.7 mols? So .....
To determine how many moles of Na3PO4 will be produced from 1.7 moles of NaOH, we need to use the balanced chemical equation:
H3PO4 + 3NaOH -> 3H2O + Na3PO4
From the equation, we can see that the stoichiometric ratio between NaOH and Na3PO4 is 3:1. This means that for every 3 moles of NaOH, we will have 1 mole of Na3PO4.
To find the number of moles of Na3PO4 produced, we can use the following calculation:
moles of Na3PO4 = (moles of NaOH) x (1 mole Na3PO4 / 3 moles NaOH)
Substituting the given value:
moles of Na3PO4 = (1.7 moles NaOH) x (1 mole Na3PO4 / 3 moles NaOH)
Now, let's calculate the result:
moles of Na3PO4 = (1.7 / 3) moles Na3PO4
= 0.567 moles Na3PO4
Therefore, 1.7 moles of NaOH will produce 0.567 moles of Na3PO4 in the presence of excess H3PO4.