Bob's age is 4 times greater than Susan's age. Dakota is 3 years younger than Susan. The sum of Bob's Susan's and Dakota's ages is 93 what is Susan's age
B + S + D = 93
B = 4S
D = S - 3
substituting ... (4 S) + S + (S - 3) = 93
To find Susan's age, we can set up a system of equations based on the given information.
Let's assume Susan's age as "S."
Given that Bob's age is 4 times greater than Susan's age, we can express Bob's age as "4S."
Also, it is given that Dakota is 3 years younger than Susan. So, Dakota's age can be expressed as "S - 3."
Now, the sum of Bob's, Susan's, and Dakota's ages is 93. So, we can set up the equation:
4S + S + (S - 3) = 93
Simplifying the equation, we have:
6S - 3 = 93
Adding 3 to both sides:
6S = 96
Dividing both sides by 6:
S = 16
Therefore, Susan's age is 16 years.