Simplify: (2x-3y4)3(x3 + y)0 / (4xy-2)3

(2x-3y^4)^3 (x^3 + y)^0 / (4xy-2)^3

(x^3+y)^0 = 1, so that just leaves

(2x-3y)^3 / (4xy-2)^3
you could expand both of those polynomials, but to what advantage, I don't know.
or, make it

((2x-3y)/(4xy-2))^3

sorry

((2x-3y^4)/(4xy-2))^3

To simplify the expression,

Step 1: Start by simplifying each term within the numerator and denominator separately.

Numerator:
(2x - 3y^4)^3(x^3 + y)^0

The power of 0 means any term raised to the power of 0 is equal to 1. Therefore, (x^3 + y)^0 simplifies to 1.

So the numerator becomes:
(2x - 3y^4)^3

Denominator:
(4xy - 2)^3

Step 2: Now, let's expand the cube of each term in the numerator and denominator.

Numerator:
(2x - 3y^4)^3 = (2x - 3y^4)(2x - 3y^4)(2x - 3y^4)

You can use the distributive property to multiply the terms and combine like terms if necessary.

Denominator:
(4xy - 2)^3 = (4xy - 2)(4xy - 2)(4xy - 2)

Again, multiply the terms using the distributive property and combine like terms.

Step 3: Simplify further if possible.

At this point, we have expanded the numerator and denominator expressions but cannot simplify any further unless we have specific values for x and y.

So the simplified expression is:
(2x - 3y^4)^3 / (4xy - 2)^3

Note: This is the simplified form, and if you have specific values for x and y, you can substitute them to evaluate the expression.