Simplify: (2x-3y4)3(x3 + y)0 / (4xy-2)3
(2x-3y^4)^3 (x^3 + y)^0 / (4xy-2)^3
(x^3+y)^0 = 1, so that just leaves
(2x-3y)^3 / (4xy-2)^3
you could expand both of those polynomials, but to what advantage, I don't know.
or, make it
((2x-3y)/(4xy-2))^3
sorry
((2x-3y^4)/(4xy-2))^3
To simplify the expression,
Step 1: Start by simplifying each term within the numerator and denominator separately.
Numerator:
(2x - 3y^4)^3(x^3 + y)^0
The power of 0 means any term raised to the power of 0 is equal to 1. Therefore, (x^3 + y)^0 simplifies to 1.
So the numerator becomes:
(2x - 3y^4)^3
Denominator:
(4xy - 2)^3
Step 2: Now, let's expand the cube of each term in the numerator and denominator.
Numerator:
(2x - 3y^4)^3 = (2x - 3y^4)(2x - 3y^4)(2x - 3y^4)
You can use the distributive property to multiply the terms and combine like terms if necessary.
Denominator:
(4xy - 2)^3 = (4xy - 2)(4xy - 2)(4xy - 2)
Again, multiply the terms using the distributive property and combine like terms.
Step 3: Simplify further if possible.
At this point, we have expanded the numerator and denominator expressions but cannot simplify any further unless we have specific values for x and y.
So the simplified expression is:
(2x - 3y^4)^3 / (4xy - 2)^3
Note: This is the simplified form, and if you have specific values for x and y, you can substitute them to evaluate the expression.