Q 31 The sum of the weights of an iron piece and of a copper piece is 1280 gm. The volume of the copper piece is twice that of the
iron piece. If the weight of 1 cubic centimeter of iron is 7.8 gm and that of copper is 8.9 gm. Find the volume of each piece
.
where is the solution
Hello don't lie you didn't even solve.
Where is the solution?
I can't find it.
To find the volume of each piece, we need to set up a system of equations based on the information given.
Let's assume the volume of the iron piece is V (in cubic centimeters). Since the volume of the copper piece is twice that of the iron piece, the volume of the copper piece is 2V.
Now, let's set up the equations based on the weights and volumes:
Equation 1: Weight of iron piece + Weight of copper piece = 1280 gm
Equation 2: Weight of iron = Volume of iron piece * Weight of 1 cubic centimeter of iron
Equation 3: Weight of copper = Volume of copper piece * Weight of 1 cubic centimeter of copper
Substituting the values from the problem, we get:
Equation 1: Weight of iron piece + Weight of copper piece = 1280 gm
Equation 2: Weight of iron = V * 7.8
Equation 3: Weight of copper = 2V * 8.9 = 17.8V
Let's substitute Equation 2 and Equation 3 into Equation 1:
V * 7.8 + 17.8V = 1280
Combine like terms:
25.6V = 1280
Divide both sides by 25.6:
V = 50
Now, we have the value of V, which represents the volume of the iron piece. We can substitute this value into Equation 3 to find the volume of the copper piece:
Volume of copper piece = 2V
Volume of copper piece = 2 * 50
Volume of copper piece = 100
Therefore, the volume of the iron piece is 50 cubic centimeters, and the volume of the copper piece is 100 cubic centimeters.
c = 2 i
7.8 i + 8.9 c = 1280
substituting ... 7.8 i + 8.9 (2i) = 1280
solve for i , then substitute back to find c