Needing some help with how to set up the problem please. Thank you.
Rashida has 3 blouses: red, white, and pink. She has 2 skirts: blue and black. She has 2 pairs of shoes: red and white. What is the probability that Rashida selects an outfit at random that does not include a blue skirt? Write the probability as a percent.
total number of outfits = 12
total number of outfits with blue skirt = 3x1x2 = 6
prob of outfit with blue skirt = 6/12 = 12
prob of outfit without blue skirt = 1 - 1/2 = 1/2
To set up the problem, we need to know the total number of possible outfits and the number of outfits that do not include a blue skirt.
Let's start by finding the total number of possible outfits. Since Rashida has 3 blouses, 2 skirts, and 2 pairs of shoes, the total number of possible outfits can be calculated by multiplying the number of options for each clothing item: 3 x 2 x 2 = 12 possible outfits.
Next, we need to determine the number of outfits that do not include a blue skirt. In this case, we have 2 options for the skirt (blue and black). Since we want to exclude the outfits with a blue skirt, we need to subtract the outfits with a blue skirt from the total number of outfits. So the number of outfits without a blue skirt is 12 total outfits - 2 outfits with a blue skirt = 10 outfits without a blue skirt.
Now, to find the probability, we divide the number of outfits without a blue skirt by the total number of outfits and express it as a percentage.
Probability = (Number of outfits without a blue skirt) / (Total number of outfits)
Probability = 10 outfits without a blue skirt / 12 total outfits
Probability = 10/12.
To express this probability as a percentage, we can multiply it by 100:
Probability = (10/12) × 100 = 83.33% (rounded to two decimal places).
Therefore, the probability that Rashida selects an outfit at random that does not include a blue skirt is approximately 83.33%.