Consider the reaction when aqueous solutions of sodium nitrate and ammonium sulfide are combined. net ionic equation?
Does a reaction occur when aqueous solutions of ammonium chloride and potassium carbonate are combined?
To determine the net ionic equation for the reaction between sodium nitrate (NaNO3) and ammonium sulfide (NH4)2S, we need to first write the balanced molecular equation, followed by the complete ionic equation, and finally identify the spectator ions to write the net ionic equation.
The molecular equation for the reaction is:
2 NaNO3(aq) + (NH4)2S(aq) → Na2S(aq) + 2 NH4NO3(aq)
To write the complete ionic equation, we separate all soluble strong electrolytes in the reaction into their respective ions:
2 Na+(aq) + 2 NO3-(aq) + 2 NH4+(aq) + S2-(aq) → Na2S(aq) + 2 NH4+(aq) + 2 NO3-(aq)
Next, we identify the spectator ions, which are the ions that appear on both sides of the equation unchanged. In this case, the NH4+ and NO3- ions are spectator ions.
Hence, the net ionic equation for the reaction is:
2 Na+(aq) + S2-(aq) → Na2S(aq)
In summary, the net ionic equation for the reaction between sodium nitrate and ammonium sulfide is 2 Na+(aq) + S2-(aq) → Na2S(aq).
To find the net ionic equation for the reaction between sodium nitrate (NaNO3) and ammonium sulfide (NH4)2S, we need to first write the balanced molecular equation and then convert it into the ionic equation.
Step 1: Write the balanced molecular equation
The balanced molecular equation for the reaction between sodium nitrate and ammonium sulfide can be written as:
NaNO3(aq) + (NH4)2S(aq) → Na2S(aq) + 2NH4NO3(aq)
Step 2: Split the compounds into ions
Now we need to split the aqueous compounds into their respective ions. Sodium nitrate dissociates into sodium cations (Na+) and nitrate anions (NO3-), while ammonium sulfide dissociates into ammonium cations (NH4+) and sulfide anions (S2-). The ionic equation becomes:
Na+(aq) + NO3-(aq) + 2NH4+(aq) + S2-(aq) → Na2S(aq) + 2NH4+(aq) + 2NO3-(aq)
Step 3: Cancel out the spectator ions
In the ionic equation above, we can see that the ammonium cation (NH4+) and nitrate anion (NO3-) appear on both sides of the equation. These ions are called spectator ions because they remain unchanged throughout the reaction. To write the net ionic equation, we need to remove the spectator ions from the equation. After canceling out the spectator ions, the net ionic equation is:
Na+(aq) + S2-(aq) → Na2S(aq)
Therefore, the net ionic equation for the reaction between sodium nitrate and ammonium sulfide is Na+(aq) + S2-(aq) → Na2S(aq).
Here is how you do these. Use this as an example to work yours.
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