Acetic acid(CH3O2H) reacts with isopentyl alcohol (C5H12O) to yield isopentyl acetate acetic acid with isopentyl alcohol is 45%,how many grams of isopentyl acetate are formed from 3.5g of accetic acid and 4.75g of isopentyl alcohol? The reaction is ;
You need to repost this question using proper sentence construction. With no periods at the end and no caps at the beginning of a sentence, I can't understand what you've written.
To determine the amount of isopentyl acetate formed from 3.5 grams of acetic acid (CH3O2H) and 4.75 grams of isopentyl alcohol (C5H12O), we need to use stoichiometry and the given reaction equation.
The reaction equation you provided is missing, but I assume it is as follows:
CH3O2H + C5H12O → isopentyl acetate + H2O
To solve this problem, we follow these steps:
Step 1: Find the number of moles of each reactant
1 mole of any substance is equal to its molar mass in grams.
The molar mass of acetic acid (CH3O2H) = 60.05 g/mol
The molar mass of isopentyl alcohol (C5H12O) = 88.15 g/mol
Number of moles of acetic acid = mass of acetic acid (in grams) / molar mass of acetic acid
Number of moles of acetic acid = 3.5 g / 60.05 g/mol
Number of moles of isopentyl alcohol = mass of isopentyl alcohol (in grams) / molar mass of isopentyl alcohol
Number of moles of isopentyl alcohol = 4.75 g / 88.15 g/mol
Step 2: Determine the limiting reactant
The limiting reactant is the one that is completely consumed in the reaction and determines the maximum amount of product that can be formed. To find the limiting reactant, we compare the number of moles of each reactant from Step 1.
Assume we have x moles of acetic acid and y moles of isopentyl alcohol.
From the balanced equation, it is known that the stoichiometric ratio is 1:1 for acetic acid to isopentyl alcohol for the formation of isopentyl acetate.
Using this knowledge, x moles of acetic acid will react with x moles of isopentyl alcohol.
To balance the equation, it must follow the stoichiometry principle.
Since we have equal moles of acetic acid and isopentyl alcohol, we can set x equal to the number of moles of acetic acid (from Step 1).
Step 3: Calculate the moles and mass of isopentyl acetate formed
From the balanced equation, it is known that the stoichiometric ratio is 1:1 for acetic acid to isopentyl acetate.
The number of moles of isopentyl acetate formed = x moles of acetic acid
Mass of isopentyl acetate formed = number of moles of isopentyl acetate × molar mass of isopentyl acetate
Therefore, the mass of isopentyl acetate formed = x moles of acetic acid × molar mass of isopentyl acetate
Step 4: Calculate the mass of isopentyl acetate formed
The molar mass of isopentyl acetate depends on the structure and can be calculated by adding the individual molar masses of its constituent elements: carbon (C), hydrogen (H), and oxygen (O).
Calculate the molar mass of isopentyl acetate (C7H14O2) by adding the molar masses of its constituent elements.
Finally, substitute the value of x from Step 2 and calculate the value of isopentyl acetate that will be formed.
Keep in mind that the given percentage (45%) might be the yield of isopentyl acetate. In that case, the actual formed mass would be 45% of the calculated value.
I hope this explanation helps you understand how to approach and solve the problem.