Question

Using your knowledge of equilibrium constants, calculate the value of K1 given the following equations:

2A+B ---> C K1=x
2B ----> D K2=5.00
2C -----> 4A+D K=0.0588

The arrows are reversible

Answer 1

(1) 2A + B ---> C K1=x

(2) 2B ==> D k2
(3) 2C --> 4A + D k3

Reverse (2) D --> 2B k = 1/k2
add to (3) 2C ==> 4A + + D k3
_________________
sum.(4).2C ==> 4A + 2B k = (1/k2)*k3 or k3/k2

Reverse (4) 4A + 2B -> 2C k = 1/k3/k2 or k2/k3 but that is just twice equation (1) so k1 = √k2/k3

Post your work if you get stuck.