Can diborane (B2H6) react with an alkene in a Hydroboration reaction or its BH3 the one that reacts so the splitting of diborane to borane has to be considered because I heard theyre the same?
I am not an organic chemist but I found this. Perhaps this will help.
https://www.masterorganicchemistry.com/reaction-guide/hydroboration-of-alkenes/
Thank you but its saying Diborane behaves the same as borane does that mean its is not converted to bh3 in this equation B2H6➡️2Bh3 I am worried about this because I want to find percentage yield of my product so i am going step by step
Please help or if you know anyone who could help please
Would you see if you can help this student.
For the hydroboration oxidation reaction, it is BH3 that gets added across the alkene double bond, with BH2 and H being added across the bond.
So for hydroboration oxidation, yes, it is BH3 that reacts.
I know I already dis the mechanism but to find percentage yield of cyclohexanol first its the formation of diborane and then do I have to split it to B2H6 ➡️2BH3 so this mole ratio is to be considered as well or is it that B2H6 and BH3 are equivalent so not considered and then the second step is oxidation using NaOH and H2O2 so I have to find LR between these two to find moles of cyclohexanol formed or I use BH3 or B2H6 please help thankyou
you use the mass of the original B2H6, the splitting is internal to the reaction.
I thought its going to be like this 2B2H6 to form 4BH3 so then no. of moles will be multiplied by 4 and divided by 2
In a hydroboration reaction, both diborane (B2H6) and BH3 can react with an alkene. However, there are some important distinctions to be aware of.
Diborane is a dimer of borane (BH3). Each diborane molecule consists of two borane units connected by a bridge of two hydrogen atoms. When diborane reacts with an alkene, it undergoes a process called "splitting" or "dissociation" to give two BH3 molecules. This splitting occurs because diborane is not reactive towards alkenes, whereas BH3 is highly reactive.
So, if you are considering the hydroboration of an alkene using diborane, it is essential to take into account the splitting of diborane to BH3. The BH3 molecules released upon dissociation will be the actual species involved in the reaction.
To summarize, when using diborane in a hydroboration reaction, it is the BH3 molecules that react with the alkene, rather than the intact diborane molecule. The splitting of diborane is necessary to generate the reactive BH3 species.