Ball B, with a mass of 30kg, is moving to the left at 10 m/s. With what velocity should Ball A, with a mass of 10kg, move to the right and collide with 2, so that ball A rebounds with a velocity of 30 m/s, and Ball B with velocity of 10 m/s, after the collision? Assume the collision to be perfectly elastic.

30(-10)+10(V)=10(+30)+30(-10)

it is unclear to me which direction B is after the collision(I assumed left above)
Left was negative, Right is positive

10V=300-300+300
V=30m/s if I got the directions correctly.

But it was elastic so B has to go right after

V = -30

before
A moving right at 30
after
A moving left at 30

before
B moving left at 10
after
B moving right at 10

speeds of both the same before and after so same Ke
momentum is zero before and after

Thank you SO MUCH!

To solve this problem, we can apply the principles of conservation of momentum and kinetic energy.

1. Conservation of momentum:
The total momentum of the system before the collision is equal to the total momentum after the collision. The equation can be written as:

(mass of ball A * velocity of ball A before the collision) + (mass of ball B * velocity of ball B before the collision) = (mass of ball A * velocity of ball A after the collision) + (mass of ball B * velocity of ball B after the collision)

Applying the values given in the problem:
(10 kg * velocity of ball A before the collision) + (30 kg * (-10 m/s)) = (10 kg * 30 m/s) + (30 kg * 10 m/s)

2. Conservation of kinetic energy:
Since the collision is perfectly elastic, the total kinetic energy before the collision is equal to the total kinetic energy after the collision. The equation can be written as:

(0.5 * mass of ball A * (velocity of ball A before the collision)^2) + (0.5 * mass of ball B * (velocity of ball B before the collision)^2) = (0.5 * mass of ball A * (velocity of ball A after the collision)^2) + (0.5 * mass of ball B * (velocity of ball B after the collision)^2)

Applying the values given in the problem:
(0.5 * 10 kg * (velocity of ball A before the collision)^2) + (0.5 * 30 kg * (-10 m/s)^2) = (0.5 * 10 kg * (30 m/s)^2) + (0.5 * 30 kg * (10 m/s)^2)

By solving these two equations simultaneously, we can find the velocity of ball A before the collision. Substituting the values and solving the equations will give us the answer.