# maths

sinA+cosA=p and secA+CosecA=q
then show that q[p^2-1]=2p

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1. q[p^2-1]
= (secA + cosecA)[(sinA+cosA)^2 - 1]
= (secA + cosecA)[ (sin^2A + cos^2A) + 2sinAcosA - 1]
= (secA + cosecA)[ 1 + 2sinAcosA - 1 ]
= (secA + cosecA)(2sinAcosA)
= 2sinA + 2cosA
= 2(sinA + cosA) = 2p

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3. Thanks

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