Given f(x) = –x3 + x2 – x – 5, find f(–3), f(0), and f(1)
Hmmmm. Put in the value of x, and compute.
Here is f(0) as an example:
f(0)=-0^3 + 0^2 -0 -5 = -5
To find f(-3), f(0), and f(1) for the function f(x) = -x^3 + x^2 - x - 5, you need to substitute the given values of x into the function and compute the result.
Let's start with f(-3):
f(-3) = -(-3)^3 + (-3)^2 - (-3) - 5
= -(-27) + 9 + 3 - 5
= 27 + 9 + 3 - 5
= 34
So, f(-3) = 34.
Next, let's calculate f(0):
f(0) = -(0)^3 + (0)^2 - (0) - 5
= -0 + 0 - 0 - 5
= -5
Therefore, f(0) = -5.
Finally, let's find f(1):
f(1) = -(1)^3 + (1)^2 - (1) - 5
= -1 + 1 - 1 - 5
= -6
Hence, f(1) = -6.
By substituting the values of x into the function and performing the corresponding calculations, you can find the values of f(-3), f(0), and f(1) for the given function.