There are 4 store fronts on the ground floor of a shopping center.

One of four stores will go in each store front – a pharmacy, grocery, barber shop, and coffee shop.
How many different possibilities are there for arranging the shops in the storefronts?

The first one has 4 choices

The second one has 3
the third one has 2
and the last one is stuck with the last one.
4*3*2 = 4!

To find the number of different possibilities for arranging the shops in the storefronts, we can use the concept of permutations.

Since there are 4 store fronts and 4 different shops (pharmacy, grocery, barber shop, and coffee shop), we need to find the number of ways to arrange these 4 shops in the 4 store fronts.

The formula for finding the number of permutations is:
P(n, r) = n! / (n - r)!

Where n is the total number of items and r is the number of items taken at a time.

In this case, we need to find P(4, 4) since we are arranging all 4 shops.

P(4, 4) = 4! / (4 - 4)!
= 4! / 0!
= 4! / 1
= 4 x 3 x 2 x 1 / 1
= 24

Therefore, there are 24 different possibilities for arranging the shops in the storefronts.