A 5.0-kg rock and a 3.8 10-4-kg pebble are held near the surface of the earth.
(a) Determine the magnitude of the gravitational force exerted on each by the earth.
F=mg
To determine the magnitude of the gravitational force exerted on each object by the Earth, we can use the formula for gravitational force:
F = m * g
Where:
F is the force,
m is the mass of the object, and
g is the acceleration due to gravity.
In this case, the mass of the rock is given as 5.0 kg, and the mass of the pebble is given as 3.8 * 10^-4 kg. The acceleration due to gravity near the surface of the Earth is approximately 9.8 m/s^2.
For the rock:
F = 5.0 kg * 9.8 m/s^2
F = 49 N
For the pebble:
F = (3.8 * 10^-4 kg) * 9.8 m/s^2
F = 3.724 * 10^-3 N
Therefore, the magnitude of the gravitational force exerted on the rock by the Earth is 49 N, and the magnitude of the gravitational force exerted on the pebble by the Earth is 3.724 * 10^-3 N.