cobalt(11)chloride is commonly obtained from chemical supply houses as a hydrate with the formula CoCl2*6H2O. An analysis showed that 25.0g of this hydrate contains 11.3g of water.What is the percent water by weight in this hydrate?
%H2O = (g H2O/g salt)*100 = ?
To find the percent water by weight in the hydrate (CoCl2*6H2O), we need to calculate the mass of water and divide it by the total mass of the hydrate, then multiply by 100 to obtain the percentage.
Given data:
Mass of the hydrate = 25.0g
Mass of water = 11.3g
First, let's find the mass of the anhydrous salt (CoCl2) in the hydrate:
Mass of anhydrous salt = Mass of hydrate - Mass of water
Mass of anhydrous salt = 25.0g - 11.3g
Mass of anhydrous salt = 13.7g
Now, we can calculate the percent of water by weight in the hydrate:
Percent water by weight = (Mass of water / Mass of hydrate) * 100
Percent water by weight = (11.3g / 25.0g) * 100
Percent water by weight = 0.452 * 100
Percent water by weight = 45.2%
Therefore, the percent water by weight in the hydrate CoCl2*6H2O is 45.2%.