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Find the probability of rolling an even number and then rolling a 6 when a number cube is rolled twice. Express the probability as percent rounded to 1 decimal place.

P(even and then a 6) =

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  1. The events are independent, so event A would be multiplied by event B. (Event A =rolling an even #) (Event B =rolling a 6).

    The probability of event A = 1/2
    The probability of event B = 1/6

    To solve:

    P(even then 6)= 1/2*1/6 = 1/12 = 0.083

    Therefore, there is approximately 0.83*100 or 8.3% chance of rolling an even number (2 or 4 or 6) followed by a six with a six sided die.

    Hope this helps :)

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  2. thanks so much!

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  3. No Problem!

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  4. I no understand

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