Find the probability of rolling an even number and then rolling a 6 when a number cube is rolled twice. Express the probability as percent rounded to 1 decimal place.

P(even and then a 6) =

The events are independent, so event A would be multiplied by event B. (Event A =rolling an even #) (Event B =rolling a 6).

The probability of event A = 1/2
The probability of event B = 1/6

To solve:

P(even then 6)= 1/2*1/6 = 1/12 = 0.083

Therefore, there is approximately 0.83*100 or 8.3% chance of rolling an even number (2 or 4 or 6) followed by a six with a six sided die.

Hope this helps :)

I no understand

Well, rolling a number cube twice is a bit like changing your mind twice before making a decision. It's quite an indecisive cube! Anyway, let's calculate the probability of this particular scenario.

First, we need to find the probability of rolling an even number. Since a standard number cube has 6 sides, and 3 of those sides are even (2, 4, and 6), the probability of rolling an even number on the first roll is 3/6 or 1/2.

Now, let's figure out the probability of rolling a 6 on the second roll. Since we already rolled once, there are only 5 possible outcomes left, and only one of them is a 6. So, the probability of rolling a 6 on the second roll is 1/5.

To find the probability of both events happening, we multiply the probabilities together: (1/2) * (1/5) = 1/10.

Now, to express this probability as a percent, we multiply by 100: (1/10) * 100 = 10%.

Therefore, the probability of rolling an even number and then rolling a 6 when a number cube is rolled twice is 10%, rounded to 1 decimal place.

Remember, probability is no laughing matter. Well, except for when I'm around!

To find the probability of rolling an even number and then rolling a 6 when a number cube is rolled twice, we can break it down into two independent events: rolling an even number and rolling a 6.

Step 1: Calculate the probability of rolling an even number
A standard number cube has 6 faces, numbered from 1 to 6. Out of these 6 numbers, exactly half (3 numbers) are even (2, 4, and 6). Therefore, the probability of rolling an even number is 3/6, which simplifies to 1/2.

Step 2: Calculate the probability of rolling a 6
Similarly, there is only one face on the number cube with the number 6. So, the probability of rolling a 6 is 1/6.

Step 3: Calculate the probability of both events happening
Since these are independent events, we can multiply the probabilities calculated in steps 1 and 2 to find the probability of both events happening: (1/2) * (1/6) = 1/12.

Step 4: Convert the probability to percent
To express the probability as a percent, we need to multiply the probability (1/12) by 100 and round to 1 decimal place: (1/12) * 100 = 8.3%.

Therefore, P(even and then a 6) is 8.3%.

thanks so much!

No Problem!