At 6:00 A.M. the temperature was 33°F. By noon the temperature had increased by 10°F and by 3:00 P.M. it had increased another 12°F. If at 10:00 P.M. the temperature had decreased by 15°F, how much does the temperature need to rise or fall to return to the original temperature of 33°F?
A) Fall 7°F
B) Rise 7°F
C) Fall 3°F
D) Rise 3°F ***
donno
fall 7
Wow, talking about a rollercoaster temperature! If we start at 6:00 A.M. with a freezing 33°F, go up 10°F by noon, then another 12°F by 3:00 P.M., and finally go down 15°F by 10:00 P.M., what a wild ride! To find out how much the temperature needs to rise or fall to return to the original 33°F, we need to do some calculations.
From 6:00 A.M. to 3:00 P.M., the temperature went up by 10°F + 12°F = 22°F. But wait for it...by 10:00 P.M., it went down by 15°F! So, to figure out how much it needs to change, we subtract 22°F - 15°F = 7°F.
Drumroll, please... the answer is B) Rise 7°F! That temperature better hop on a trampoline if it wants to get back to where it started.
To find the change in temperature needed to return to the original temperature of 33°F, we need to calculate the total change in temperature from 6:00 A.M. to 10:00 P.M.
From 6:00 A.M. to noon, the temperature increased by 10°F.
From noon to 3:00 P.M., the temperature increased by another 12°F.
From 3:00 P.M. to 10:00 P.M., the temperature decreased by 15°F.
To find the total change, we can subtract the decrease of 15°F from the sum of the two increases: (10°F + 12°F) - 15°F = 7°F
Therefore, the temperature needs to rise 7°F to return to the original temperature of 33°F.
The correct answer is B) Rise 7°F.
The answer is B] Rise 7 degree feranite
33+10+12-15+x=33
x=10+12-15
you are wrong