AB and CD are two parallel chords of a circle whose centre is O and radius is 20cm.If Ab=24cm and CD=32cm find distance between AB and CD. If it's given that they lie. 1.onthe opposite sides of centreO. 2.on the same side of the centre o.
I will do same side
one radius is 12, the other 16
to find center to the 12 radius
12^2 + h^2 = 20^2
144 + h^2 = 400
256 = h^2
h = 16
now to the 16 radius
256 + h^2 = 400
h = 12
so distance between = 4 (part B)
now if the 12 is on the other side of center we have 12 + 16 = 28(part A)
Damon didn't mean radius, he meant half of the chord length
draw the picture and you will see
To find the distance between the parallel chords AB and CD, we need to use the concept of the perpendicular distance between parallel lines.
1. When the chords AB and CD lie on opposite sides of the center O:
In this case, we can draw radii from the center O to the points where the chords AB and CD intersect the circumference of the circle. Let's call these points E and F, respectively. The line EF is perpendicular to both AB and CD.
To find the distance between AB and CD, we can use the following steps:
1. Draw the radii OE and OF, which have the same length since O is the center of the circle (20 cm).
2. Connect points E and F to form the line EF.
3. Measure the length of EF using a ruler or any other measuring tool. This length will give you the distance between AB and CD.
2. When the chords AB and CD lie on the same side of the center O:
In this case, we can extend the chords AB and CD on both sides until they intersect. Let's call the points of intersection G and H, respectively. The line GH is perpendicular to both AB and CD.
To find the distance between AB and CD, we can use the following steps:
1. Extend the chords AB and CD on both sides until they intersect and form points G and H.
2. Connect points G and H to form the line GH.
3. Measure the length of GH using a ruler or any other measuring tool. This length will give you the distance between AB and CD.
Note: Ensure that the ruler or measuring tool is accurately aligned with the given dimensions of AB (24 cm) and CD (32 cm) to get an accurate measurement of the distance between the chords.