A farmer sold 2/3 of his cattle.he gave 1/6 of the cattle to his son.what fraction of cows does he still have?
To find the fraction of cows the farmer still has, we need to subtract the fractions he sold (2/3) and the fraction he gave to his son (1/6) from 1 (which represents the whole).
1 - 2/3 - 1/6
To subtract fractions, we need a common denominator. The common denominator of 3 and 6 is 6. So, we rewrite the fractions with this denominator:
1 - (4/6) - (1/6)
Now, we can subtract:
(6/6) - (4/6) - (1/6)
This simplifies to:
1/6
Therefore, the farmer still has 1/6 of his cattle.
To find the fraction of cows the farmer still has, we need to subtract the fraction of cows he sold from the fraction he gave to his son.
The farmer sold 2/3 of his cattle, which means he has 1 - 2/3 = 1/3 of his cattle remaining.
He also gave 1/6 of the cattle to his son, so we need to subtract 1/6 from the 1/3 the farmer has remaining.
To subtract fractions, we need a common denominator. In this case, the least common denominator of 3 and 6 is 6.
Converting the fractions to have a denominator of 6, we have:
1/3 = 2/6
1/6 = 1/6
Subtracting 1/6 from 2/6, we get:
2/6 - 1/6 = 1/6
So the farmer still has 1/6 of the cattle remaining.
Therefore, the fraction of cows the farmer still has is 1/6.
4/6 + 1/6 = 5/6
so, ...