How many moles of carbon dioxide would be produced if 0.28 moles of propane, C3H8, were combusted? C3H8 + 5 O2 --> 3 CO2 + 4 H20

C3H8 + 5 O2 --> 3 CO2 + 4 H20

This shows that for every mole of propane combusted, three moles of carbon dioxide are produced.

Now, we have 0.28 moles of propane.

1 mol of C3H8 -> 3 mol of CO2
0.28 * 1 mol of C3H8 -> 0.28 * 3 mol of CO2
0.28 mol of C3H8 -> 0.84 mol of CO2

3.7g

To determine the number of moles of carbon dioxide produced from the combustion of 0.28 moles of propane (C3H8), we can use the stoichiometry of the chemical equation provided:

C3H8 + 5 O2 → 3 CO2 + 4 H2O

From the balanced equation, we can see that for every 3 moles of carbon dioxide (CO2) produced, 1 mole of propane (C3H8) is consumed.

Therefore, we can set up a proportion to solve for the number of moles of carbon dioxide produced:

(0.28 moles of propane) / (1 mole of propane) = (x moles of carbon dioxide) / (3 moles of carbon dioxide)

Cross-multiplying the above proportion we get:

0.28 moles of propane = x/3

Solving for x, we multiply both sides of the equation by 3:

x = 0.28 moles of propane * 3 = 0.84 moles of carbon dioxide

Therefore, 0.28 moles of propane would produce 0.84 moles of carbon dioxide.