the specific heat capacity of solid copper metal is 0.385 j/g k. Calculate temperature rise of 100g bar of copper when 250J of heat is transferred into it?

hmmm. seems to me like pretty straightforward. I don't have the formula handy, but to convert J to °K, I'd do

250J * 1g°K/0.385J / 100g = 6.49°K

To calculate the temperature rise of the copper bar, you can use the formula:

q = m * c * ΔT

Where:
q is the heat energy transferred (in Joules),
m is the mass of the copper bar (in grams),
c is the specific heat capacity of copper (in J/g·K),
ΔT is the change in temperature (in Kelvin).

From the question, we know that:
q = 250 J
m = 100 g
c = 0.385 J/g·K

Rearranging the formula, we can solve for ΔT:

ΔT = q / (m * c)
ΔT = 250 J / (100 g * 0.385 J/g·K)

Calculating ΔT:
ΔT = 250 J / (38.5 g·K)
ΔT ≈ 6.49 K

Therefore, the temperature of the copper bar will rise by approximately 6.49 K when 250 J of heat is transferred into it.

To calculate the temperature rise of a substance, we can use the formula:

ΔT = Q / (m * C)

Where:
ΔT is the temperature rise,
Q is the heat transferred,
m is the mass of the substance, and
C is the specific heat capacity.

Now, let's plug in the given values into the formula:

Q = 250 J (heat transferred)
m = 100 g (mass of copper)
C = 0.385 J/g°C (specific heat capacity of copper)

ΔT = 250 J / (100 g * 0.385 J/g°C)

First, we need to convert the specific heat capacity to J/gK to match the unit of mass in grams with the unit of temperature in Kelvin. We can do this by adding 273 to the value:

C = 0.385 J/gK
C = 0.385 J/g°C + 273

Now, let's calculate the temperature rise:

ΔT = 250 J / (100 g * C)

Substituting the value of C we calculated:

ΔT = 250 J / (100 g * (0.385 J/g°C + 273))
ΔT = 250 J / (100 g * 273.385 J/g°C)

Now, we can calculate the temperature rise ΔT:

ΔT = 0.00913 °C

Therefore, the temperature rise of the 100 g bar of copper when 250 J of heat is transferred into it is approximately 0.00913 °C.