tan 39°=40/AP, So AP =40/tan. in triangle AQP, angle Q= 60/sin 91°=AP/SinQ. Then bearing of Qfrom P = 30° 180°-(91 angle Q).
40/tan makes no sense
To find the value of AP, we can use the trigonometric equation tan(39°) = 40/AP. Rearranging this equation, we get AP = 40/tan(39°).
Next, to find the value of angle Q in triangle AQP, we can use the trigonometric equation sin(91°) = AP/sin(Q). Rearranging this equation, we get sin(Q) = AP/sin(91°). Since sin(Q) = sin(180° - Q), we can use this property to rewrite the equation as sin(180° - Q) = AP/sin(91°).
Now, to find the bearing of Q from P, we use the fact that the bearing is measured relative to the north direction from a particular point, usually P. In this case, the bearing of Q from P is given as 30° - (91° - angle Q). This is because the angle between the north direction and the line connecting P and Q is 91°, and we subtract this from the given angle Q to find the bearing.