Algebra
I know this is very simple for some but i find it hard to get the roots, so please bear with me and help me. Thank you.
x^3  2x2 + 1 = 0.
asked by
Michael

x^32x^2+0x+1=0
well, one way is to graph
y=x^32x^2+1 and look at the roots.
another way is to factor.
by inspection x=1 is a root, so divide by x1 to get the remaining polynomial
(x^32x^2+0x+1)/(x1) and I get by long division x^2x1, and that can be factored by the quadratic equation.posted by bobpursley
Respond to this Question
Similar Questions

algebra
simplify:(3x0 ynegative 4)(2x2 y)3 this is hard to break down but i got 6x6/y but my sister said it could either be 24x6/y or 216x6/y6 if not any break it down and tell me which one is right thank u please keep it clear and simple 
algebra
so the answer is 6 x6/y or 24 x6/y simplify:(3x0 ynegative 4)(2x2 y)3 this is hard to break down but i got 6x6/y but my sister said it could either be 24x6/y or 216x6/y6 if not any break it down and tell me which one is right 
Algebra 2
If f(x)= x2 + 2x  6 and g(x)= 3x2  5x  7, find f(x)g(x). A) 2x2  3x + 1 B) 2x2 + 7x + 1 C) 2x2  3x  13 <my choice D) 4x2  3x  13 
algebra
simplify:(3x0 ynegative 4)(2x2 y)3 this is hard to break down but i got 6x6/y but my sister said it could either be 24x6/y or 216x6/y6 if not any break it down and tell me which one is right thank u please keep it clear and simple 
Algebra
Solve. (–10x3 + 30x – 20) ÷ (–5x + 5) • 2x2 – 2x + 4 • –2x2 – 2x – 4 • –2x2 + 2x + 4 • 2x2 + 2x – 4 How? 
algebra 2
What is the number of distinct possible rational roots of p(x)=2x2+7x+6? I need help on how to solve this 
Algebra 2
How do I solve this quadratic function by finding square roots 2x²=200 ? 
ALGEBRA 2 PLEASE HELP
How do I solve this quadratic function by finding square roots 2x²=200 ? 
math
(please solve step by step) solving equation (6x+2)/4 + (2x²1)/(2x²+2) = (10x1)/4x we got roots as 
college algebra
Radical and Rational Exponent find roots square roots of 12a^3/25=6a^3 3square roots 18/6=1 this is my answer am I right. check this for me it find the roots of the problem