If 6.64 moles of C5H12 reacts with excess O2, how many moles of CO2 will be produced in the following combustion reaction?
Can plz explain how to do it
Thank You
balance the equation;
C5H12+ 8O2 >>> 5CO2 + 6H2O
so you get 5x the number of moles you used of Pentane.
I do not see your reaction.
I will assume:
1 C5H12 + 8O2 --> 5CO2 + 6H2O
so
6 molecules or mols of C5H12
gives
6*5 = 30 molecules or mols of CO2
How do you get 6 molecules or mols of C5H12
I mean how did you get the number 5
The whole numbers on teach compound tells you the mole ratios..
To find the number of moles of CO2 produced in the combustion reaction, you need to use the balanced chemical equation and the stoichiometry of the reaction.
Here is the balanced chemical equation for the combustion of C5H12:
C5H12 + 8O2 → 5CO2 + 6H2O
From the balanced equation, we can see that for every mole of C5H12, 5 moles of CO2 are produced.
Given that you have 6.64 moles of C5H12, you can set up a proportion to find the number of moles of CO2:
6.64 moles C5H12 x 5 moles CO2
----------------- = -------------
1 ?
By cross-multiplying and dividing, you can solve for the unknown value, which represents the number of moles of CO2. In this case, it is calculated as:
(6.64 moles C5H12 * 5 moles CO2) / 1 mole C5H12 = 33.2 moles CO2.
Therefore, when 6.64 moles of C5H12 react with excess O2, 33.2 moles of CO2 will be produced in the combustion reaction.