A boy yells towards a clikff and hears his echo 3.15 s later. If the air temperature is 12 degrees C, how far away is the cliff?

The distance the sound travels is twice distance.

2d=velocitysound*time

Now for velocitysound at 12C... You have a formula for that, I have long forgotten it, it goes something like this

vsound=330(1+.6Temp) m/s
check that.

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To determine the distance to the cliff, we can use the formula for sound velocity at a given temperature. The formula is:

vsound = 330 m/s + 0.6 * temperature

In this case, the temperature is given as 12 degrees Celsius. Plugging this value into the formula, we can calculate the velocity of sound in air at this temperature:

vsound = 330 m/s + 0.6 * 12 degrees Celsius = 330 m/s + 7.2 m/s = 337.2 m/s

Next, we use the fact that the distance the sound travels is twice the distance to the cliff. Let's denote the distance to the cliff as 'd'.

Using the formula for distance:

2d = vsound * time

The time given in the question is 3.15 seconds. Substituting the values into the formula:

2d = 337.2 m/s * 3.15 seconds

Simplifying:

2d = 1062.78 m

Divide both sides of the equation by 2:

d = 531.39 m

Therefore, the distance to the cliff is approximately 531.39 meters.