In this experiment 4.0g of ferrous ammonium sulfate is used. Assuming everything else is added in excess; calculate the theoretical yield of the iron complex. Work through the entire reaction sequence; do not simply assume the number of moles of limiting reaction equals the number of moles of your final product.

To calculate the theoretical yield of the iron complex, we need to follow the reaction sequence and determine the limiting reactant. Let's break down the reaction step by step:

1. Write the balanced equation for the reaction:
Fe(NH4)2(SO4)2 · 6H2O + H2C2O4 · 2H2O + H2SO4 → FeC2O4 · 2H2O + (NH4)2SO4 + 4H2O

2. Calculate the molar mass of ferrous ammonium sulfate (Fe(NH4)2(SO4)2 · 6H2O):
Fe: 1 * 55.85 g/mol = 55.85 g/mol
(NH4)2(SO4)2: 2 * (14.01 + 1.01 * 4 + 32.06 * 2) = 392.24 g/mol
6H2O: 6 * (2 * 1.01 + 16.00) = 108.08 g/mol

Molar mass of Fe(NH4)2(SO4)2 · 6H2O:
55.85 + 392.24 + 108.08 = 556.17 g/mol

3. Calculate the number of moles of ferrous ammonium sulfate used:
n = m/M
n = 4.0 g / 556.17 g/mol ≈ 0.00719 mol

4. Calculate the molar mass of the iron complex (FeC2O4 · 2H2O):
FeC2O4: 1 * 55.85 + 2 * (12.01 + 16.00) = 143.87 g/mol
2H2O: 2 * (2 * 1.01 + 16.00) = 36.03 g/mol

Molar mass of FeC2O4 · 2H2O:
143.87 + 36.03 = 179.90 g/mol

5. Now, we have to determine the limiting reactant to determine the theoretical yield. To do this, we need to compare the moles of each reactant to the mole ratio from the balanced equation.

From the balanced equation:
Fe(NH4)2(SO4)2 : H2C2O4 : FeC2O4 = 1 : 1 : 1

Based on this ratio, we can see that the moles of ferrous ammonium sulfate are equal to the moles of the iron complex.

Therefore, the theoretical yield of the iron complex is:
0.00719 mol

Note: In this scenario, we assumed that all the other reactants (H2C2O4, H2SO4) are in excess, meaning there will be no limitation by their quantities when reacting with ferrous ammonium sulfate.

To calculate the theoretical yield of the iron complex, we need to determine the limiting reactant and the balanced chemical equation for the reaction.

Step 1: Determine the balanced equation for the reaction:
The reactants mentioned are ferrous ammonium sulfate (Fe(NH4)2(SO4)2) and an excess of other reactants. Unfortunately, the complete reaction equation is not provided. Please provide the complete equation to proceed further.

Once you provide the balanced equation, I can assist in calculating the theoretical yield.

balance the equation. from the 4 g o ferrous ammonium sulfate, how much of that 4g is IRON?

so the blanced equation give you the mole relations:
how many moles of ferrous ammonum sulfate did you start with. From that, how many moles of the iron complex?
now, multiply that by the percent of iron in the original complex.