If two light bulbs are choosen at random from 5 bulbs of which are defective then which of the following in the probability that none in defective?
1/10
2/10
2/7
2/8
Typo?
If 2 are chosen from 5 defective bulbs, all would be defective.
2/8
To find the probability that none of the chosen light bulbs are defective, we need to calculate the probability of choosing a non-defective bulb each time.
Let's break down the problem step by step.
Step 1: Determine the total number of ways to choose 2 light bulbs out of the 5 available bulbs. This can be calculated using the combination formula, denoted as "C(5,2)" which equals 10.
Step 2: Determine the number of ways to choose 2 non-defective bulbs out of the 3 non-defective bulbs. Since we have 3 non-defective bulbs and we need to choose 2 of them, we can use the combination formula again: "C(3,2)" which equals 3.
Step 3: Calculate the probability of choosing 2 non-defective bulbs. The probability can be calculated by dividing the number of favorable outcomes (ways of choosing 2 non-defective bulbs) by the total number of possible outcomes (ways of choosing any 2 bulbs). Therefore, the probability is given by:
P(no defective bulbs) = Number of favorable outcomes / Total number of possible outcomes
P(no defective bulbs) = C(3,2) / C(5,2)
P(no defective bulbs) = 3 / 10
Therefore, the probability that none of the chosen bulbs are defective is 3/10.
So, out of the given options, the probability that none of the bulbs is defective is 3/10, which is not listed.
@PsyDAG
Yes that was typo."3" is missing in above. Here is the correct :
If two light bulbs are choosen at random from 5 bulbs of which 3 are defective then which of the following in the probability that none in defective?
1/10
2/10
2/7
2/8