How many capacitor of 4uF capacity each are combined to get total capacity of 6uF
You could do this if you use three 4uF capacitors in the following arrangement:
C1 and C2 in series, and then the equivalent arrangement of C1 and C2 in parallel with C3.
Calculate the equivalent capacitances and see why that works.
We start by connecting three 4uF capacitors in parallel which gives us a 12uF capacitor. Now if we connect three more 4uF capacitors in parallel, we'll have two 12uF capacitors. Now if we connect these two 12uF capacitors in series, we'll have exactly 6uF:
C = C1*C2/(C1+C2).
C = 12*12/(12+12) = 6uF.
To determine the number of 4uF capacitors needed to achieve a total capacity of 6uF, we can use the formula:
Total capacity = Capacity of each capacitor × Number of capacitors
In this case, we have a total capacity of 6uF and a capacity of each capacitor as 4uF. Let's assume the number of capacitors needed is "n."
So, the equation becomes:
6uF = 4uF × n
To solve for "n," we can divide both sides of the equation by 4uF:
6uF / 4uF = n
This simplifies to:
1.5 = n
Therefore, you would need 1.5 capacitors of 4uF capacity each to achieve a total capacity of 6uF. However, since you cannot have a fraction of a capacitor, you would need to round up to the nearest whole number.
Thus, you would need 2 capacitors of 4uF capacity each to obtain a total capacity of 6uF.