# Algebra

Let g(x)=3x+2 and f(x)=(x-2)/3 Find the value. f(g(0))

I think I figured out part of it.

g(0)=3(0)+2=2
g(2)=3(2)+2=8
f(8)=((8)-2)/3=6/3=2

If this is correct, idk where to go from here.

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1. Your first step, g(0)=3(0)+2=2, is correct.

f(g(0)) means that you plug in the value of 'g(0)' as x in f(x).

g(0) = 2
f(g(0)) = f(2) = (2-2)/3 = 0

This is all your question asks for, but these functions are actually inverses of each other. So f(g(x)) and g(f(x)) will always be equal to x.

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posted by Arora
2. I actualy found a khan academy thing that helped me out a few minutes ago, before i saw this, but thank you anyways! <3

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