Find the equation of the line
With a slope of (-1/3) that goes through the point (2, -4)
With a slope of 3 that goes through the point (-5, -1)
y=mx+b
(x,y)
You multiply x by m, the slope.
You get to y by adding b.
(2,-4)
You multiply 2 (x) by -1/3 (m), the slope.
You get to -4 (y) by adding -3.33 (b) = -10/3
Therefore, y=(-1/3)x-(10/3)
The next one is done the same way.